I am a beginner in python. I am currently using Beautifulsoup to scrape a website.
str='' #my_url
source = urllib.request.urlopen(str);
soup = bs.BeautifulSoup(source,'lxml');
match=soup.find('article',class_='xyz');
for paragraph in match.find_all('p'):
str+=paragraph.text+"\n"
My tag Structure -
<article class="xyz" >
<h4>dr</h4>
<p>efkl</p>
<h4>dr</h4>
<p>efkl</p>
<h4>dr</h4>
<p>efkl</p>
<h4>dr</h4>
<p>efkl</p>
</article>
I am getting output like this (as I am able to extract the paragraphs) -
efkl
efkl
efkl
efkl
Output I want ( I want the headings as well as the paragraphs) -
dr
efkl
dr
efkl
dr
efkl
dr
efkl
I want my output to also contains headings along with paragraphs.How to modify code in such a way that it contains header before paragraphs (Like in original HTML) .
You can peel the same apple in different ways to serve the purpose. Here are few of them:
Using .find_next():
from bs4 import BeautifulSoup
content="""
<article class="xyz" >
<h4>dr</h4>
<p>efkl</p>
<h4>dr</h4>
<p>efkl</p>
<h4>dr</h4>
<p>efkl</p>
<h4>dr</h4>
<p>efkl</p>
</article>
"""
soup = BeautifulSoup(content,"lxml")
for items in soup.find_all(class_="xyz"):
data = '\n'.join(['\n'.join([item.text,item.find_next("p").text]) for item in items.find_all("h4")])
print(data)
Using .find_previous_sibling():
for items in soup.find_all(class_="xyz"):
data = '\n'.join(['\n'.join([item.find_previous_sibling("h4").text,item.text]) for item in items.find_all("p")])
print(data)
Commonly used approach: multiple tags used within list:
for items in soup.find_all(class_="xyz"):
data = '\n'.join([item.text for item in items.find_all(["h4","p"])])
print(data)
All the three approaches produce the same result:
dr
efkl
dr
efkl
dr
efkl
dr
efkl
Collected from the Internet
Please contact [email protected] to delete if infringement.
Comments