How do I simplify the boolean expression A+A'BC+BC'?
user3599109
I'm trying to solve this:
So far I have:
a) a+b+c
b) a+bc
c) a+b
d) a+b
But for e) I can't progress further since I don't know how to deal with a'bc in this case. Can anyone help?
gior91
e) The expression is [a + (~a)bc + (~b)c]
a + [(~a)b + (~b)]c we can say that [(~a)b + (~b)] <--> [(~a) + (~b)] (Prove it by yourself:-)
a + [(~a) + (~b)]c
a + (~a)c + (~b)c we can say that [a + (~a)c] <--> [a + c]
a + c + (~b)c it is obvious that [c + (~b)c] <--> [c]
So [a + c] is the reduced expression.
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