I have an array:
const arr = [
{
name: "name 1",
dontShow: true,
children: [
{
name: "name 2",
key4: 4,
dontShow: false,
children: [],
},
],
},
{
name: "name 3",
dontShow: false,
children: [
{
name: "name 4",
dontShow: true,
children: [
{
name: "name 5",
dontShow: false,
children: null,
},
],
},
],
},
];
I need an array of names from every object, except those that have property dontShow: true So from that example I would expect such array:
["name2", "name3", "name5"]
Basically, I need to get a flat array from tree-like structure, lodash/underscore solutions would be also great, I just didn't find them
You can use a recursive function
const arr = [{ name: "name 1", dontShow: true, children: [{ name:"name 2", key4: 4, dontShow: false, children: [], }, ],},{name: "name 3",dontShow: false,children: [{ name: "name 4", dontShow: true, children: [{ name: "name 5", dontShow: false, children: null,},],}, ],},];
let final = (arr, result = []) => {
if (Array.isArray(arr)) {
arr.forEach(obj => {
if (!obj.dontShow) {
result.push(obj.name)
}
if (Array.isArray(obj.children)) {
final(obj.children, result)
}
})
}
return result
}
console.log(final(arr))Collected from the Internet
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