How to search multiple same values and look if it meets the conditions without regex? Suppose that I have this string ***6**5****8*9***2 What I need to do is to check if the string has at least three times *** altogether and then if the number before and after the *** sums 11. In the example given, these conditions are met because: First, the string has three *** altogether, and then 9 + 2 is 11.
I have solved this problem using regex, match, and replace, but how I can do it without applying to those solutions.
I have tried to do this without regex but it did not work because indexOf is only giving me one result:
string = "***6**5****8*9***2";
for (var i = 0; i < string.length; i++) {
let where = (string.indexOf("***"));
let a = parseInt(string.charAt(where - 1));
let b = parseInt(string.charAt(where + 3));
if (a + b == 11){
isTrue = true;
}
}
You could split the string by stars amd keep the starts in the array then check if the value starts with a star, check the length and the left and right element for sum.
var string = "***6**5****8*9***2",
parts = string.split(/(\*+)/),
result = parts.some((s, i, { [i - 1]: l, [i + 1]: r }) =>
s[0] === '*' && s.length >= 3 && +l + +r === 11
);
console.log(result);
console.log(parts);Collected from the Internet
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