The python code (python3)
import time
import urllib.response, requests
from config.dev import CONTENT_IMAGE_UPLOAD
directory = CONTENT_IMAGE_UPLOAD + "en_" + time.strftime('%Y%m%d')
filename = "sample.jpg"
try:
urllib.request.urlretrieve("https://www.miamiherald.com/latest-news/wfeh98/picture238148999/alternates/LANDSCAPE_1140/Screenshot%20(150).png", directory + "/" + filename)
print("image is saved")
except Exception as e:
print(e)
I am expecting to get the image in just less than one minute , but it take too long then print output as message like below.
[Errno 60] Operation timed out
I am sure the image is already exist because when I copied and pasted I got the image, but it seem the URL contains some special char in this part Screenshot%20(150).png,
How could I solve this error?
You should add user agent to bypass this issue, I never use urllib directly I usually use requests as it's easier for me, you can implement the same concept using urllib if you want, but you will need to look that up, here's a sample code
import time
import urllib.response, requests
# from config.dev import CONTENT_IMAGE_UPLOAD
headers = {"user-agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/78.0.3904.108 Safari/537.36"}
# directory = CONTENT_IMAGE_UPLOAD + "en_" + time.strftime('%Y%m%d')
filename = "sample.jpg"
try:
resp = requests.get("https://www.miamiherald.com/latest-news/wfeh98/picture238148999/alternates/LANDSCAPE_1140/Screenshot%20(150).png", headers=headers).content
with open(filename, "wb") as f:
f.write(resp)
print("image is saved")
except Exception as e:
print(e)
This might help you :)
Collected from the Internet
Please contact [email protected] to delete if infringement.
Comments