Swap values in dictionary which contain list of dictionaries?

Aditya Published at Dev

Aditya

I have dictionary which contain list of dictionaries as below.

I want to swap all values of list of dictionary based on name.

Example: swap_function('Arvind','Jayesh') should swap other values like surname, fullname & email.

I have already tried a lot from other website's references but not able achieve my goal.

data = {
   "items":[
      {                 
         "name":"Arvind",
         "surname":"Patel",
         "fullname":"Arvind Patel",
         "email":"[email protected]"        
      },
      {        
         "name":"Jayesh",
         "surname":"Patel",
         "fullname":"Jayesh Patel",
         "email":"[email protected]"
      },
      {        
         "name":"Krishna",
         "surname":"dave",
         "fullname":"Krishna dave",
         "email":"[email protected]"
      },
      {        
         "name":"Aditya",
         "surname":"Patel",
         "fullname":"Aditya Patel",
         "email":"[email protected]"
      }

   ]
}

I have tried like below but after that I am out of ideas.

def name_swap(name1, name2):

   for key, item in data.items():
      first_dict = item[0]
      second_dict = item[1]
      third_dict = item[2]
      forth_dict = item[3]
      fifth_dict = item[4]

after name_swap('Arvind', 'Krishna')

output : 
data = {
   "items":[
      {                 
         "name":"Arvind",
         "surname":"dave",
         "fullname":"Krishna dave",
         "email":"[email protected]"        
      },
      {        
         "name":"Jayesh",
         "surname":"Patel",
         "fullname":"Jayesh Patel",
         "email":"[email protected]"
      },
      {        
         "name":"Krishna",
         "surname":"Patel",
         "fullname":"Arvind Patel",
         "email":"[email protected]"
      },
      {        
         "name":"Aditya",
         "surname":"Patel",
         "fullname":"Aditya Patel",
         "email":"[email protected]"
      }

   ]
}

Massifox

Try this code:

i = next(i for i,item in enumerate(data['items']) if item['name'] == 'Arvind')
j = next(i for i,item in enumerate(data['items']) if item['name'] == 'Krishna')
data['items'][i]['name'], data['items'][j]['name'] = 'Krishna', 'Arvind'

And gives:

{'items': [{'name': 'Arvind',
   'surname': 'dave',
   'fullname': 'Krishna dave',
   'email': '[email protected]'},
  {'name': 'Jayesh',
   'surname': 'Patel',
   'fullname': 'Jayesh Patel',
   'email': '[email protected]'},
  {'name': 'Krishna',
   'surname': 'Patel',
   'fullname': 'Arvind Patel',
   'email': '[email protected]'},
  {'name': 'Aditya',
   'surname': 'Patel',
   'fullname': 'Aditya Patel',
   'email': '[email protected]'}]}

Ok now let's generalize this example, with the following function:

def swap_dict_list(dict_list, val1, val2, target='name', block_target=True):   
    try:
        i = next(i for i,item in enumerate(dict_list) if item[target] == val1)
        j = next(i for i,item in enumerate(dict_list) if item[target] == val2)
    except StopIteration:
        return dict_list
    dict_list[i], dict_list[j] = dict_list[j], dict_list[i]
    if block_target:
        dict_list[i][target], dict_list[j][target] = val1, val2
    return dict_list

In your case, you will use the function in this:

data['items'] = swap_dict_list(data['items'], 'Arvind', 'Krishna', target='name', block_target=True)

And you will get the same result shown above.

Code explenation

The swap_dict_list function receives as input the list of dictionaries 'dict_list', the 2 values to search ('val1' and 'val2') and the dictionary key on which to perform the target search.

The function finds the indexes corresponding to the two values searched for, and if they both exist it performs the swap. If block_target is True, the target values are not exchanged.

The search is effected efficiently using generator expression.

Collected from the Internet

Please contact [email protected] to delete if infringement.