PHP的MySQL代码不会回声

巴基·尤克塞尔(Baki Yuksel)

我得到以下代码:

    if(isset($_SESSION['user_id'])) { $query = "SELECT * FROM watchlist,movies WHERE watchlist.page=movies.id AND userid=". $_SESSION['user_id']; 
    $result = mysql_query($query) or die('Query failed: ' . mysql_error());

    while( $row = mysql_fetch_assoc($result) )
      {
        echo '<div id="watchlist">';
            echo '<a href="watch.php?id='.$row['page'].'"><img src="http://nocmmnt.com/posters/'.$row['imdb_id'].'.jpg" height="217" width="154"></a><br>';
            echo '<span style="float:right;"><a href="delete.php?wid='.$row['wid'].'"><img src="image/close_delete.png" width="20"></a></span><a href="watch.php?id='.$row['page'].'">'.$row['title'].'</a><br>';  
            echo "</div>";
      }
    elseif(empty($row)) {
        echo "You dont have any movies in your watchlist!";
    }

我的问题是当它为空时没有回声怎么解决?

echo_Me

尝试:

   if(mysql_num_rows($result) == 0)
  { echo "You dont have any movies in your watchlist!"; }
  else{
  while( $row = mysql_fetch_assoc($result) )
  {
    echo '<div id="watchlist">';
        echo '<a href="watch.php?id='.$row['page'].'"><img src="http://nocmmnt.com/posters/'.$row['imdb_id'].'.jpg" height="217" width="154"></a><br>';
        echo '<span style="float:right;"><a href="delete.php?wid='.$row['wid'].'"><img src="image/close_delete.png" width="20"></a></span><a href="watch.php?id='.$row['page'].'">'.$row['title'].'</a><br>';  
        echo "</div>";
  }

  }

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