我有2个对象数组;
// First one :
[0: {id: 1},
1: {id: 2},
2: {id: 3},
3: {id: 4}]
// Second one :
[0: {id: 10},
1: {id: 1},
2: {id: 4},
3: {id: 76},
4: {id: 2},
5: {id: 47},
6: {id: 3}]
我想测试第二个是否至少具有与第一个相同的ID。在这种情况下,这是正确的,因为第二个包含1、2、3和4个ID。
我尝试使用some()和every(),但无法正常工作
我的尝试:
let res = this.trainingEpisodesList.some( episode => {
this.completedEpisodes.every( userEpisode => {
userEpisode.id == episode.id;
})
});
谢谢 ;)
let completedEpisodes =
[
{id: 1},
{id: 2},
{id: 3},
{id: 4}
]
let trainingEpisodesList =
[
{id: 10},
{id: 1},
{id: 4},
{id: 76},
{id: 2},
{id: 47},
{id: 3}
]
let containsAllCompleted = trainingEpisodesList.every(c => completedEpisodes.find(e=>e.id==c.id));
console.log(containsAllCompleted);
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