检查数组的所有元素是否包含在另一个数组中

foxer 发表于 Dev

狐狸

我想检查包含URL的unorderedPhrases数组中是否存在数组中的所有音频文件名result。如果都存在returntrue和if-else return false。

这是我尝试过的。我不知道为什么它总是返回false！

let result = [

  "https://example.com/test/unordered/i was sent to earth to protect you_A/i was sent.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to earth.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to protect you.mp3",

];

const unorderedPhrases = [

    'i was sent',
    'to earth',
    'to protect you'

];

function checkResults(){
	
    return unorderedPhrases.every(r=> result.includes(r));

 
}

console.log(checkResults())

上面的代码应该返回true，因为数组中unorderedPhrases存在所有音频文件result。

如果我们有这个数组，那么它应该返回，false因为其中有一个unorderedPhrases不存在的项目result：

let result = [
  "https://example.com/test/unordered/i was sent to earth to protect you_A/i was sent.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to earth.mp3",
];

一定的表现

如果要忽略文件夹结构，而仅考虑最后的内容，则可以先从每个result项目中删除文件夹部分，将其变成另一个数组，然后遍历短语，检查数组是否没有文件夹部分包括短语加.mp3：

let result = [
  "https://example.com/test/unordered/i was sent to earth to protect you_A/i was sent.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to earth.mp3",
  "https://example.com/test/unordered/i was sent to earth to protect you_A/to protect you.mp3",
];

const resultWithoutFolders = result.map(str => str.split('/').pop());

const unorderedPhrases = [
  'i was sent',
  'to earth',
  'to protect you'
];

function checkResults() {
  return unorderedPhrases.every(
    phrase => resultWithoutFolders.includes(phrase + '.mp3')
  );
}

console.log(checkResults())

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