我有一个充满.pdf和.dwf文件的数据库。我需要重命名这些。
这些文件的名称如下：
123456 text text.pdf
并且应如下所示：
123456000_text_text.text.pdf
我可以使用以下命令替换空格：
dir | rename-item -NewName {$_.name -replace " ","_"}
现在，我需要一个命令在前6位数字后插入3次“ 0”。
有人能帮我吗？
已经谢谢你了
您仅需要过滤* .pdf和* .dwf文件，并且文件名是否符合以6位数字开头和空格字符开头的条件。然后，您可以像这样使用正则表达式替换：
Get-ChildItem -Path D:\Test -File | Where-Object { $_.Name -match '^\d{6} .*\.(dwf|pdf)$' } |
Rename-Item -NewName { $_.Name -replace '^(\d{6}) ', '${1}000_' -replace '\s+', '_'}
之前：
D:\TEST
123456 text text.dwf
123456 text text.pdf
123456 text text.txt
后：
D:\TEST
123456 text text.txt
123456000_text_text.dwf
123456000_text_text.pdf
文件名-match的正则表达式详细信息：
^ Assert position at the beginning of the string
\d Match a single digit 0..9
{6} Exactly 6 times
\ Match the character “ ” literally
. Match any single character that is not a line break character
* Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
\. Match the character “.” literally
( Match the regular expression below and capture its match into backreference number 1
Match either the regular expression below (attempting the next alternative only if this one fails)
dwf Match the characters “dwf” literally
| Or match regular expression number 2 below (the entire group fails if this one fails to match)
pdf Match the characters “pdf” literally
)
$ Assert position at the end of the string (or before the line break at the end of the string, if any)
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