我有一个表格模式数组对象，如下所示，直到n级。可以是任何父母子女的记录
var records = [
{ country: "USA", state: "FLORIDA", city: "city1" },
{ country: "USA", state: "FLORIDA", city: "city2" },
{ country: "USA", state: "FLORIDA", city:"city3" },
{ country: "USA", state: "ALASKA" },
{ country: "USA", state: "ALBAMA" },
]
var columns = ["country","state","city"] // upto n column
我需要将以下格式分组为n级，因为可以有n个关系，将记录按以下格式分组
{
sequencer: 1, value: 'USA', loop: [
{ sequencer: 1, value: 'FLORIDA', loop: [
{ sequencer: 1, value: 'city1' },
{ sequencer: 2, value: 'city2' },
{ sequencer: 3, value: 'city3' },
], },
{ sequencer: 2, value: 'ALASKA' },
{ sequencer: 3, value: 'ALBAMA' },
],
}
有人可以编写一个递归函数来对n级列对象进行分组。谢谢
您可以通过避免不必要的循环属性来对数据进行分组。
const
data = [{ country: "USA", state: "FLORIDA", city: "city1" }, { country: "USA", state: "FLORIDA", city: "city2" }, { country: "USA", state: "FLORIDA", city: "city3" }, { country: "USA", state: "ALASKA" }, { country: "USA", state: "ALBAMA" }],
keys = ['country', 'state', 'city'],
result = data.reduce((loop, o) => {
keys
.map(k => o[k])
.filter(Boolean)
.reduce((r, value) => {
let temp = (r.loop ??= []).find(q => q.value === value);
if (!temp) r.loop.push(temp = { sequence: r.loop.length + 1, value });
return temp;
}, { loop });
return loop;
}, []);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句