如何基于对象数组更新复杂的json对象

帕拉维

我有2个数据结构，如下所示

data1：

{
  purchaceOrder: [{
      name: "Purchase Order",
      version: 1,
      description: "purchase order process",
      saved: true,
      visibility: true
    },
    {
      name: "Purchase Order",
      version: 2,
      description: "purchase order process",
      saved: false,
      visibility: true
    }
  ],
  requestOrder: [{
      name: "Request Order",
      version: 1,
      description: "request order process",
      saved: true,
      visibility: true
    },
    {
      name: "Request Order",
      version: 2,
      description: "request order process",
      saved: false,
      visibility: true
    }
  ],
  cancelOrder: [{
    name: "Cancel Order",
    version: 1,
    description: "cancel order process",
    saved: false,
    visibility: false
  }]
}

数据2：

[
  {
    id: "dwffrgefg68964",
    name: "Purchase Order",
    version: 1
  },
  {
    id: "emffrgefg68964",
    name: "Purchase Order",
    version: 2
  },
  {
    id: "iuffrgefg68964",
    name: "request Order",
    version: 1
  }
]

我想根据名称过滤data1，将data2中的id添加到data1中的每个对象，如果在data2中找不到进程名称，则删除data1中的整个对象/空数组，如下所示

最后结果：

{
  purchaceOrder: [{
      id: "dwffrgefg68964"
      name: "Purchase Order",
      version: 1,
      description: "purchase order process",
      saved: true,
      visibility: true
    },
    {
      id: "emffrgefg68964"
      name: "Purchase Order",
      version: 2,
      description: "purchase order process",
      saved: false,
      visibility: true
    }
  ],
  requestOrder: [{
    id: "iuffrgefg68964"
    name: "Request Order",
    version: 1,
    description: "request order process",
    saved: true,
    visibility: true
  }]
}

我尝试了各种解决方案，但无法获得预期的结果。这就是我所拥有的：

getAllProcess(){
for (let key in data1) {
  var temp1 = data1[key];
  for (let i = 0; i < temp1.length; i++) {
      const reqModel = data2.find(process=> process.name === temp1[i].name&& process.version === temp1[i].version);
    if(reqModel){
      temp1[i].id=reqModel.id;
        data1[key][i]=temp1[i];
    }
    }}
    return data1;
}

缺口

您的代码已关闭；您只需要删除以下条目中data1没有相应值的条目data2：

let data1 = {
  purchaseOrder: [{
      name: "Purchase Order",
      version: 1,
      description: "purchase order process",
      saved: true,
      visibility: true
    },
    {
      name: "Purchase Order",
      version: 2,
      description: "purchase order process",
      saved: false,
      visibility: true
    }
  ],
  requestOrder: [{
      name: "Request Order",
      version: 1,
      description: "request order process",
      saved: true,
      visibility: true
    },
    {
      name: "Request Order",
      version: 2,
      description: "request order process",
      saved: false,
      visibility: true
    }
  ],
  cancelOrder: [{
    name: "Cancel Order",
    version: 1,
    description: "cancel order process",
    saved: false,
    visibility: false
  }]
};

let data2 = [{
    id: "dwffrgefg68964",
    name: "Purchase Order",
    version: 1
  },
  {
    id: "emffrgefg68964",
    name: "Purchase Order",
    version: 2
  },
  {
    id: "iuffrgefg68964",
    name: "Request Order",
    version: 1
  }
];

function getAllProcess() {
  for (let key in data1) {
    var temp1 = data1[key];
    for (let i = temp1.length - 1; i >= 0; i--) {
      const reqModel = data2.find(process => process.name === temp1[i].name && process.version === temp1[i].version);
      if (reqModel) {
        temp1[i].id = reqModel.id;
        data1[key][i] = temp1[i];
      } else {
        data1[key].splice(i, 1);
      }
    }
    if (!data1[key].length) {
      delete data1[key];
    }
  }
  return data1;
}

console.log(getAllProcess());

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