新的类实例继承了以前的实例值

信号4

我正在编写一个实现双向链接列表的小树类:

class node(object): 
def __init__(self, level=0, pieces=0, parent=None,
             root=None, childNo=None, avgN=2): 

    self.level       = level   # Current level in the tree. Zero = top.
    self.pieces      = pieces  # Number of children. Can be constant or Poisson chosen random.
    self.parent      = parent  # Parent of this node.
    self.child       = {}      # Children of this node. Using a dictionary means
                               # the root could have direct access\
                               # to all children.
    self.childrenID  = {}
    self.myID        = childNo # This node's index in the parents self.child list.

    if (root == None):         # If I'm the root, then hey, I'm the root!
        self.root   = self
    else:
        self.root   = root

    self.avgN          = avgN
    self.numOfChildren = 0
    self.pieces        = self.avgN



def print_all_data(self):
    print "Printing all data for node:",self.myID
    obj_attr = [a for a in dir(n) if not a.startswith('__') and not callable(getattr(n,a))]
    for ob in obj_attr:
        print ob, getattr(n,ob)
    return


# This function acutally adds a child node to this parent.
def add_child_node(self, childno):

    self.numOfChildren        += 1
    if (self.numOfChildren > self.pieces):
        print "Error: number of children exceeds the number of assigned pieces"
        print "       for node:", self.myID

    childno                             = self.compute_new_child_ID(self.level, self.numOfChildren)
    self.childrenID[self.numOfChildren] = childno
    self.child[childno]                 = self.get_new_node(childno)

    return

def get_new_node(self,childno):

    return node(level=self.level+1, parent=self,
                root=self.root, childNo=childno,
                avgN=self.avgN)

def compute_new_child_ID(self, level, childno):
    return (level+1)*100 + childno
def get_child_no_from_child_ID(self, level, childID):
    return childID - (level+1)*100

请注意,某些功能看起来是重复的,但这些是将来使用的占位符。

现在,如果我创建一个实例,我将得到:

n = node()
n.print_all_data()

Printing all data for node: None
avgN 2
child {}
childrenID {}
level 0
myID None
numOfChildren 0
parent None
pieces 2
root <__main__.node object at 0x7fb33dc0ae10>

但是,添加任何子级都会导致它们继承父级的属性:

n.add_child_node(0)
n.add_child_node(1)
n.print_all_data()

Printing all data for node: None
avgN 2
child {101: <__main__.node object at 0x7fb33dc46350>, 102: <__main__.node object at 0x7fb33dc460d0>}
childrenID {1: 101, 2: 102}
level 0
myID None
numOfChildren 2
parent None
pieces 2
root <__main__.node object at 0x7fb33dc0ae10>

这是子数据:

n.child[101].print_all_data()

Printing all data for node: 101
avgN 2
child {101: <__main__.node object at 0x7fb33dc46350>, 102: <__main__.node object at 0x7fb33dc460d0>}
childrenID {1: 101, 2: 102}
level 0
myID None
numOfChildren 2
parent None
pieces 2
root <__main__.node object at 0x7fb33dc0ae10>

同样,创建一个新节点将继承此旧实例数据:

n2 = node()
n2.print_all_data()

Printing all data for node: None
avgN 2
child {101: <__main__.node object at 0x7fb33dc46350>, 102: <__main__.node object at 0x7fb33dc460d0>}
childrenID {1: 101, 2: 102}
level 0
myID None
numOfChildren 2
parent None
pieces 2
root <__main__.node object at 0x7fb33dc0ae10>

现在,我在StackOverflow上进行了全面搜索,并且没有使用init(这些是实例属性),也没有在函数定义中不正确地初始化不可变的字典在此处进一步说明)。我在SO中找不到其他与我的问题匹配的示例,因此提出了新问题。非常感谢您的协助。

大卫·费伦奇·罗戈赞

实例是正确的,您只是在打印错误的数据。

在该方法中print_all_data,您始终在打印变量引用n实例的属性(该变量是从更高范围继承的,并且无论使用哪种实例,它始终引用您的“根”节点),而不是打印当前实例的属性(self参考)。

在方法中print_all_data,您需要类似以下内容(当前实例由变量引用self):

obj_attr = [a for a in dir(self)
            if not a.startswith('__') and not callable(getattr(self, a))]

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