按最近日期对数组排序，如果同一天只允许一个日期

LisaN 发表于 Dev

口服

我有一个日期数组，我想对其进行排序并仅获取最近的日期

["Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)",
 "Fri Jul 13 2018 09:33:46 GMT+0200 (CEST)",
 "Fri Jul 13 2018 09:21:36 GMT+0200 (CEST)",
 "Fri Jul 13 2018 09:03:42 GMT+0200 (CEST)",
 "Fri Jul 13 2018 09:01:05 GMT+0200 (CEST)",
 "Fri Jul 13 2018 08:53:23 GMT+0200 (CEST)",
 "Fri Jul 13 2018 08:52:33 GMT+0200 (CEST)",
 "Thu Jul 12 2018 13:41:59 GMT+0200 (CEST)",
 "Thu Jul 12 2018 13:41:49 GMT+0200 (CEST)",
 "Thu Jul 12 2018 13:41:42 GMT+0200 (CEST)"]

日期是字符串，我设法对它们进行排序并得到我想要的，但是问题是我将它们作为对象而不是字符串

  datesFiltered = [];
const array = this.users.map(a => a.date)
      for (const date of array) {
          if (!this.datesFiltered.find(d => new Date(d).setHours(0, 0, 0)
            === new Date(dateString).setHours(0, 0, 0))) {
            this.datesFiltered.push(new Date(dateString))
          }
        }

结果：

    [
 Mon Jul 16 2018 15:32:50 GMT+0200 (Central European Summer Time),
 Fri Jul 13 2018 09:33:46 GMT+0200 (Central European Summer Time), 
 Thu Jul 12 2018 13:41:59 GMT+0200 (Central European Summer Time) 
    ]

代替：

  [
     "Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)",
     "Fri Jul 13 2018 09:33:46 GMT+0200 (CEST)" 
     "Thu Jul 12 2018 13:41:59 GMT+0200 (CEST)" 
        ]

尼基尔·阿格瓦尔（Nikhil Aggarwal）

您可以创建一个Set用于唯一日期的日期，并根据该日期过滤出Set使用中存在值的那些日期Array.filter

var array = ["Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)","Fri Jul 13 2018 09:33:46 GMT+0200 (CEST)","Fri Jul 13 2018 09:21:36 GMT+0200 (CEST)","Fri Jul 13 2018 09:03:42 GMT+0200 (CEST)","Fri Jul 13 2018 09:01:05 GMT+0200 (CEST)","Fri Jul 13 2018 08:53:23 GMT+0200 (CEST)","Fri Jul 13 2018 08:52:33 GMT+0200 (CEST)","Thu Jul 12 2018 13:41:59 GMT+0200 (CEST)","Thu Jul 12 2018 13:41:49 GMT+0200 (CEST)","Thu Jul 12 2018 13:41:42 GMT+0200 (CEST)"];
 
 var set = new Set();
 var array = array.filter(a => {
  var d = new Date(a).setHours(0, 0, 0);
  if(set.has(d)) return false;
  else set.add(d);
  return true;
 });
 console.log(array);

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