如何查找此数组是否有重复的对象，其中有另一个数组

萨罗伊·雷格米

无论ID如何，我都需要知道重复的数据。

这是数组：-

const myArray = [
  {id: "sjdh1", userName: "user 1"  , Message: ["try","test","test"]},
  {id: "sjdh2", userName: "user 2"  , Message: ["test","try","test"]},
  {id: "sjdh3", userName: "user 3"  , Message: ["test"]}, 
  {id: "sjdh4", userName: "user 1"  , Message: ["dummy"]},
  {id: "sjdh5", userName: "user 1"  , Message: ["try","test","test"]},
]

我想删除重复的数据。id没关系

预期的结果是：-

const myArray = [
  {id: "sjdh1", userName: "user 1"  , Message: ["try","test","test"]},
  {id: "sjdh2", userName: "user 2"  , Message: ["test","try","test"]},
  {id: "sjdh3", userName: "user 3"  , Message: ["test"]}, 
  {id: "sjdh4", userName: "user 1"  , Message: ["dummy"]}, 
]

如果UserName和Message数组完全相同，则删除值如果Message数组不同，则删除该值，则不应将该对象视为重复的对象：

因此，我尝试使用set方法，但是我发现它不起作用，因为myArray包含该对象。

然后我用谷歌搜索了问题并得到了解决方案，但是它对我没有用：-

 const uniqueValues = new Set(array.map(v => v.name));

它给了我唯一的价值

阿比舍克·库马尔（Abhishek Kumar）

现在就足够了：

const myArray = [
    {id: "sjdh1", userName: "user 1"  , Message: ["try","test","test"]},
    {id: "sjdh2", userName: "user 2"  , Message: ["test","try","test"]},
    {id: "sjdh3", userName: "user 3"  , Message: ["test"]}, 
    {id: "sjdh4", userName: "user 1"  , Message: ["dummy"]},
    {id: "sjdh5", userName: "user 1"  , Message: ["try","test","test"]},
  ]
function unique(){
    const uniqueKeys = ['userName','Message'];
    const keys = ['id'];
    const uniqueObj = {}
    myArray.forEach((arrObj)=>{
        const strKey = {};
        const strObj = {};
        uniqueKeys.forEach((k)=>{
            strKey[k] = arrObj[k]
        });
        keys.forEach((key)=>{
            strObj[key] = arrObj[key];
        })
        if(!uniqueObj[JSON.stringify(strKey)])
            uniqueObj[JSON.stringify(strKey)] = strObj;
    });
    const output = Object.keys(uniqueObj).map((key)=>{
        return {
            ...uniqueObj[key],
            ...JSON.parse(key)
        }
    })
    console.log(output);
}

unique();

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