熊猫并排堆积的条形图

PyRsquared

我想创建一个钛酸数据集的堆叠条形图。该情节需要按“ Pclass”，“ Sex”和“ Survived”分组。我已经通过大量乏味的numpy操作做到了这一点，以产生下面的归一化图（其中“ M”是男性，“ F”是女性）

有没有办法使用熊猫内置的绘图功能来做到这一点？

我已经试过了：

import pandas as pd
import matplotlib.pyplot as plt
df = pd.read_csv('train.csv')
df_grouped = df.groupby(['Survived','Sex','Pclass'])['Survived'].count()
df_grouped.unstack().plot(kind='bar',stacked=True,  colormap='Blues', grid=True, figsize=(13,5));

这不是我想要的。无论如何，有没有使用熊猫图制作第一个图？提前致谢

Fuglede

生成的条形图将不会像第一个图那样彼此相邻，但是除此之外，pandas允许您执行以下操作：

df_g = df.groupby(['Pclass', 'Sex'])['Survived'].agg([np.mean, lambda x: 1-np.mean(x)])
df_g.columns = ['Survived', 'Died']
df_g.plot.bar(stacked=True)

在此，补丁的水平分组由于堆叠的要求而变得复杂。例如，如果我们只关心“生存”的价值，那么大熊猫可以开箱即用。

df.groupby(['Pclass', 'Sex'])['Survived'].mean().unstack().plot.bar()

如果临时解决方案足以对地块进行后处理，那么这样做也不会太复杂：

import numpy as np
from matplotlib import ticker

df_g = df.groupby(['Pclass', 'Sex'])['Survived'].agg([np.mean, lambda x: 1-np.mean(x)])
df_g.columns = ['Survived', 'Died']
ax = df_g.plot.bar(stacked=True)

# Move back every second patch
for i in range(6):
    new_x = ax.patches[i].get_x() - (i%2)/2
    ax.patches[i].set_x(new_x)
    ax.patches[i+6].set_x(new_x)

# Update tick locations correspondingly
minor_tick_locs = [x.get_x()+1/4 for x in ax.patches[:6]]
major_tick_locs = np.array([x.get_x()+1/4 for x in ax.patches[:6]]).reshape(3, 2).mean(axis=1)
ax.set_xticks(minor_tick_locs, minor=True)
ax.set_xticks(major_tick_locs)

# Use indices from dataframe as tick labels
minor_tick_labels = df_g.index.levels[1][df_g.index.labels[1]].values
major_tick_labels = df_g.index.levels[0].values
ax.xaxis.set_ticklabels(minor_tick_labels, minor=True)
ax.xaxis.set_ticklabels(major_tick_labels)

# Remove ticks and organize tick labels to avoid overlap
ax.tick_params(axis='x', which='both', bottom='off')
ax.tick_params(axis='x', which='minor', rotation=45)
ax.tick_params(axis='x', which='major', pad=35, rotation=0)