错误：分段错误，核心转储，在 c 编程中

迪维亚斯里 K.

以下 c 编程代码给出了核心转储分段错误，请告诉我为什么我会收到此错误，并通过提供此代码的更正版本来帮助我。谢谢！

#include <stdio.h>
#include <string.h>
 
int main()
{
    char str[100], ch;
    int i, Flag;
    Flag = 0;
 
    printf("\n Please Enter any String :  ");
    fgets(str,sizeof(str),stdin);
    printf("%s",str);
    printf("\n Please Enter the Character that you want to replace with :  ");
    scanf("%c", &ch);
    
    for(i = 0; i <= strlen(str); i++)
    {
          str[i]=ch;    
      }
    str[i]='\0';
    
    printf("\n The characters have been found and replaced with %c and they occur %d times ", ch, i + 1);
    printf("The replaced string is %s ",str);
    
    return 0;
}

凯尔

尝试这个。

#include <stdio.h>
#include <string.h>
 
int main()
{
    char str[100], ch;
    int i, Flag;
    Flag = 0;
 
    printf("\n Please Enter any String :  ");
    fgets(str,sizeof(str),stdin);
    printf("%s",str);
    printf("\n Please Enter the Character that you want to replace with :  ");
    scanf("%c", &ch);
    
    for(i = 0; i < strlen(str); i++) //change <= to < 
    {
          str[i]=ch;      
      }
    str[i]='\0';
    
    printf("\n The characters have been found and replaced with %c and they occur %d times ", ch, i + 1);
    //printf("The replaced string is %s ",str);
    
    return 0;
}

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