如何使用 PHP 从数组中提取多个 JSON 对象？

Maks 发表于 Dev

最大限度

我一直在试图弄清楚如何从 json 数组中提取多个 JSON 对象。

我使用了其他帖子中的此代码

$json = '[
            {"user_id":"1",
            "user_name":"Sayeed Amin",
            "time":"2019-11-06 13:21:26"}
        ]';

$someArray = json_decode($json, true);

foreach ($someArray as $key => $value) {
    echo $value["user_id"] . ", " . $value["user_name"] . ", " . $value["time"] . "<br>";
}

我可以将它用于数组中的单个 json 对象，结果很好。

结果：1，赛义德·阿明，2019-11-06 13:21:26

如果我在里面有多个 json 对象和数组怎么样？像

$json = '[
        {"name":"Name",
        "value":"me you",
        "id":0,
        "type":"name",
        "first":"me",
        "middle":"",
        "last":"you"
        },
        {"name":"Email",
        "value":"[email protected]",
        "id":1,
        "type":"email"
        },
        {"name":"Phone",
        "value":"+12015550000",
        "id":2,"type":"phone"
        },
        {"name":"Address",
        "value":"my address\nsomecity, somestate\nsomepost\nUS",
        "id":3,
        "type":"address",
        "address1":"my address",
        "address2":"",
        "city":"somecity",
        "state":"somestate",
        "postal":"somepost",
        "country":"US"
        }
]';

$someArray = json_decode($json, true);

foreach ($someArray as $key => $value) {
    echo $value["name"] . ", " . $value["value"] . "<br>";
}

结果：姓名，我，你的
电子邮件，[email protected]
电话，+12015550000
地址，我的地址 somecity，somestate somestate somepost US

想要的结果：名字，我，你

里格斯愚蠢

如果您只想输出对象数组的第一次出现，则适当地对数组进行寻址，例如

$json = '[
        {"name":"Name",
        "value":"me you",
        "id":0,
        "type":"name",
        "first":"me",
        "middle":"",
        "last":"you"
        },
        {"name":"Email",
        "value":"[email protected]",
        "id":1,
        "type":"email"
        },
        {"name":"Phone",
        "value":"+12015550000",
        "id":2,"type":"phone"
        },
        {"name":"Address",
        "value":"my address\nsomecity, somestate\nsomepost\nUS",
        "id":3,
        "type":"address",
        "address1":"my address",
        "address2":"",
        "city":"somecity",
        "state":"somestate",
        "postal":"somepost",
        "country":"US"
        }
]';

$arr = json_decode($json);

echo $arr[0]->name . ", " . $arr[0]->value . "\n";

结果