如何为依赖于使用cocoapods添加的其他框架的所有架构构建可可触摸框架？

我想为为模拟器和设备构建的输出框架创建一个私有的cocoapod。

我创建了一个Cocoa触摸框架，其中使用Cocoapods集成了CocoaLumberjack。我想为所有可能的架构（模拟器和设备）构建框架。

默认情况下，构建设置

 'Build Active Architectures Only' is set to (Debug - Yes, Release - No).

一旦将此调试设置设置为“否”，构建将失败，并显示以下链接器错误：

Undefined symbols for architecture i386:
"_OBJC_CLASS_$_DDASLLogger", referenced from:
  objc-class-ref in MyManager.o
"_OBJC_CLASS_$_DDLog", referenced from:
  objc-class-ref in MyManager.o
"_OBJC_CLASS_$_DDTTYLogger", referenced from:
  objc-class-ref in MyManager.o
ld: symbol(s) not found for architecture i386
clang: error: linker command failed with exit code 1 (use -v to see invocation)

我知道CocoaLumberjack仅适用于调试版本中的活动架构。

因此，我将“构建用于调试的活动体系结构”切换回“是”，并成功构建了框架。

为了构建适用于所有架构的框架，我使用了在构建阶段中添加的运行脚本，该脚本还声称将ios-device和ios-simulator构建合并为一个。这是脚本：

    set -e
    set +u
    # Avoid recursively calling this script.
    if [[ $SF_MASTER_SCRIPT_RUNNING ]]
    then
    exit 0
    fi
    set -u
    export SF_MASTER_SCRIPT_RUNNING=1


    # Constants
    SF_TARGET_NAME=${PROJECT_NAME}
    UNIVERSAL_OUTPUTFOLDER=${BUILD_DIR}/${CONFIGURATION}-universal

    # Take build target
    if [[ "$SDK_NAME" =~ ([A-Za-z]+) ]]
    then
    SF_SDK_PLATFORM=${BASH_REMATCH[1]}
    else
    echo "Could not find platform name from SDK_NAME: $SDK_NAME"
    exit 1
    fi

    if [[ "$SF_SDK_PLATFORM" = "iphoneos" ]]
    then
    echo "Please choose iPhone simulator as the build target."
    exit 1
    fi

    IPHONE_DEVICE_BUILD_DIR=${BUILD_DIR}/${CONFIGURATION}-iphoneos

    # Build the other (non-simulator) platform
    xcodebuild -project "${PROJECT_FILE_PATH}" -target "${TARGET_NAME}" -configuration "${CONFIGURATION}" -sdk iphoneos BUILD_DIR="${BUILD_DIR}" OBJROOT="${OBJROOT}" BUILD_ROOT="${BUILD_ROOT}" CONFIGURATION_BUILD_DIR="${IPHONE_DEVICE_BUILD_DIR}/arm64" SYMROOT="${SYMROOT}" ARCHS='arm64' VALID_ARCHS='arm64' $ACTION

    xcodebuild -project "${PROJECT_FILE_PATH}" -target "${TARGET_NAME}" -configuration "${CONFIGURATION}" -sdk iphoneos BUILD_DIR="${BUILD_DIR}" OBJROOT="${OBJROOT}" BUILD_ROOT="${BUILD_ROOT}"  CONFIGURATION_BUILD_DIR="${IPHONE_DEVICE_BUILD_DIR}/armv7" SYMROOT="${SYMROOT}" ARCHS='armv7 armv7s' VALID_ARCHS='armv7 armv7s' $ACTION

    # Copy the framework structure to the universal folder (clean it first)
    rm -rf "${UNIVERSAL_OUTPUTFOLDER}"
    mkdir -p "${UNIVERSAL_OUTPUTFOLDER}"
    cp -R "${BUILD_DIR}/${CONFIGURATION}-iphonesimulator/${PROJECT_NAME}.framework" "${UNIVERSAL_OUTPUTFOLDER}/${PROJECT_NAME}.framework"

    # Smash them together to combine all architectures
    lipo -create  "${BUILD_DIR}/${CONFIGURATION}-iphonesimulator/${PROJECT_NAME}.framework/${PROJECT_NAME}" "${BUILD_DIR}/${CONFIGURATION}-iphoneos/arm64/${PROJECT_NAME}.framework/${PROJECT_NAME}" "${BUILD_DIR}/${CONFIGURATION}-iphoneos/armv7/${PROJECT_NAME}.framework/${PROJECT_NAME}" -output "${UNIVERSAL_OUTPUTFOLDER}/${PROJECT_NAME}.framework/${PROJECT_NAME}"

我选中运行脚本下方的“仅在安装时运行脚本”复选框。现在，我为通用iOS设备构建框架。现在，我单击Project层次结构中存在的Products组，然后选择MyFramework.framework文件，右键单击并选择在finder中显示。它会在finder中打开〜/ Library / Developer / Xcode / DerivedData / MyFramework-dlpsipmxkqmemwgqrfeovlzgyhca / Build / Products / Debug-iphoneos / MyFramework.framework。

Now, I create a new tag 'MyFramework-v0.0.1' containing the commit where I added MyFramework.framework file. 

我转到〜/ .cocoapods / repos / MyRepoName /并创建一个podspec文件MyFramework.podspec，如下所示：

Pod::Spec.new do |s|
s.name         = "MyFramework"
s.version      = "0.0.1"
s.summary      = "A pod for MyFramework"
s.description  = "A pod designed for MyFramework"

s.homepage     = "My_Private_Repo_Path"
s.license      = { :type => "MIT", :file => "FILE_LICENSE" }
s.authors             = { "My_Username" => "my_email_address"
}
s.platform     = :ios, "8.0"
s.ios.deployment_target = "8.0"

s.source       = { :git => "My_Private_Repo_Path", :tag => 'MyFramework-v'+String(s.version) }

s.requires_arc = true
s.vendored_frameworks = "MyFramework.framework"
s.dependency "CocoaLumberjack"
end

现在，当我在终端中运行以下命令时：

pod repo push MyRepoName MyFramework.podspec

我收到以下错误：

Validating spec
-> MyFramework (0.0.1)
- ERROR | [iOS] xcodebuild: Returned an unsuccessful exit code. You can use `   --verbose` for more information.
- NOTE  | [iOS] xcodebuild:  ld: warning: ignoring file  MyFramework/MyFramework.framework/MyFramework, missing required architecture i386 in file   MyFramework/MyFramework.framework/MyFramework (2 slices)
- NOTE  | [iOS] xcodebuild:  ld: warning: ignoring file MyFramework/MyFramework.framework/MyFramework, missing required architecture x86_64 in file MyFramework/MyFramework.framework/MyFramework (2 slices)
- NOTE  | [iOS] xcodebuild:  fatal error: lipo: -remove's specified would result in an empty fat file

[!] The `MyFramework.podspec` specification does not validate.

如何为所有设备和模拟器构建可可触摸框架，该框架依赖于使用可可豆添加的另一个框架（CocoaLumberjack）？我需要为输出框架创建一个私有容器。