接受用户输入时如何运行相同功能

我想制作一个基本的类似于游戏的控制台程序...所以，问题是，当用户输入为N / n时，如果没有任何错误，如何使同一功能再次运行....这是我的代码。当我输入N / n时，它将变成图片... Im使用Visual Studio C ++ 2015。先感谢您

#include "stdafx.h"
#include <iostream>
#include <stdio.h>
#include <cstdio>
#include <string>
#include <iomanip>
using namespace std;

string name;
int age;
char prompt;

void biodata()
{
    cin.clear();
    cout << "Name : ";  getline(cin, name);
    cout << "Age : "; cin >> age;
}

void showBio()
{
    cin.clear();
    cout << "Thank you for providing your data...";
    cout << "\nPlease confirm your data...(Y/N)\n" << endl;

    //printing border
    cout << setfill('-') << setw(1) << "+" << setw(15) << "-" << setw(1) << "+" << setw(15) << "-" << setw(1) << "+" << endl;
    //printing student record
    cout << setfill(' ') << setw(1) << "|" << setw(15) << left << "Name" << setw(1) << "|" << setw(15) << left << "Age" << setw(1) << "|" << endl;
    //printing border
    cout << setfill('-') << setw(1) << "+" << setw(15) << "-" << setw(1) << "+" << setw(15) << "-" << setw(1) << "+" << endl;
    //printing student record
    cout << setfill(' ') << setw(1) << "|" << setw(15) << left << name << setw(1) << "|" << setw(15) << left << age << setw(1) << "|" << endl;
    //printing border
    cout << setfill('-') << setw(1) << "+" << setw(15) << "-" << setw(1) << "+" << setw(15) << "-" << setw(1) << "+" << endl;
    //printing student record

    cin >> prompt;

}

int main()
{
    cout << "Hi User, my name is Cheary. I'm your Computated Guidance (CG), nice to meet you..." << endl;
    cout << "Please provide your data..." << endl;
    biodata();
    showBio();

    if (prompt == 'Y' || 'y')
    {
        cout << "Thank you for giving cooperation...\nWe will now proceed to the academy..." << endl;
    }

    while (prompt == 'N' || 'n')
    {
        cout << "Please re-enter your biodata..." << endl;
        biodata();
        showBio();
    }

    system("pause");
    return 0;
}