添加缺少的行,但不更改日期

轮圈

我正在尝试将缺失的行添加到数据帧中(在每个NO_REF值之内),同时在某些列上进行线性插值,并在另一些列上插入最后一个非NA值。当间隔之后的DATE_X值大于间隔之前的最后一个DATE值时,我无法弄清楚如何防止插入缺失的日期。

这是我的数据框:

df = data.frame(DATE = as.Date(c("2016-01-31","2016-03-31","2016-05-31","2016-08-31","2016-12-31","2016-02-29","2016-04-30","2016-06-30","2016-08-31","2016-10-31","2016-12-31","2015-01-31","2015-02-28","2015-06-30","2015-10-31","2015-12-31")), 
            DATE_X = as.Date(c("2010-01-31","2010-01-31","2016-04-30","2015-03-31","2015-03-31","2010-10-31","2010-10-31","2016-05-31","2016-05-31","2015-07-31","2015-07-31","2013-01-31","2013-01-31","2013-01-31","2015-09-30","2015-09-30")),
            NO_REF = c("P1","P1","P1","P2","P2","O1","O1","O1","O1","R1","R2","Q1","Q1","Q1","Q1","Q1"),
            KAP = as.double(15:30),
            DIV =c("PI","PI","PI","PI","PI","OP","OP","OP","OP","PR","PR","OP","OP","OP","OP","OP"))

这是我的代码:

library(dplyr)
library(multidplyr)
library(zoo)

cluster <- create_cluster(3)
cluster_eval(cluster,library(dplyr))
cluster_eval(cluster,library(zoo))

result = df %>% partition(NO_REF,cluster=cluster) %>%
group_by(NO_REF) %>%
do(left_join(data.frame(NO_REF = .$NO_REF[1], DATE = seq(min(.$DATE)+1, max(.$DATE)+1, by="1 month")-1), ., 
           by=c("NO_REF","DATE"))) %>%  mutate(DATE_X=na.locf(DATE_X, na.rm=FALSE),
             DIV=na.locf(DIV, na.rm=FALSE), KAP=na.approx(KAP)) %>% collect()

在下表中,蓝色行不应位于最终结果中。

预期结果:

在此处输入图片说明

预先感谢您的帮助!

mpjdem

这可能不是最有效的方法,但是我认为它可以满足您的要求:

library(dplyr)
library(multidplyr)
library(zoo)

cluster <- create_cluster(3)
cluster_eval(cluster,library(dplyr))
cluster_eval(cluster,library(zoo))

result = df %>% partition(NO_REF,cluster=cluster) %>%
    group_by(NO_REF) %>%
    do(left_join(data.frame(NO_REF = .$NO_REF[1], DATE = seq(min(.$DATE)+1, max(.$DATE)+1, by="1 month")-1), ., 
       by=c("NO_REF","DATE"))) %>%  
    filter(!(is.na(DATE_X) & 
             na.locf(DATE_X, fromLast=TRUE, na.rm=FALSE)>
             na.locf(DATE+days(ifelse(is.na(DATE_X), NA, 0)), na.rm=FALSE))) %>% 
    mutate(DATE_X=na.locf(DATE_X, na.rm=FALSE),
           DIV=na.locf(DIV, na.rm=FALSE), 
           KAP=na.approx(KAP)) %>% 
    collect()

简而言之,该DATE列被视为NA并在DATE_X缺少的地方继续前进,DATE_X向后携带,在缺少时后者大于前者的行将DATE_X被删除。

本文收集自互联网,转载请注明来源。

如有侵权,请联系 [email protected] 删除。

编辑于
0

我来说两句

0 条评论
登录 后参与评论

相关文章