我有如下字典:
dt = {'2016-12-15 18:12:17': 1, '2016-12-15 17:40:39': 1, '2016-12-15 15:53:42': 1, '2016-12-15 15:51:41': 1, '2016-12-15 15:49:55': 1, '2016-12-15 15:49:54': 1, '2016-12-15 15:48:05': 1, '2016-12-15 15:27:38': 1, '2016-12-15 09:05:03': 1, '2016-12-15 08:43:45': 1, '2016-12-15 07:29:15': 1, '2016-12-15 05:56:58': 1, '2016-12-14 14:33:31': 1, '2016-12-14 14:33:30': 1, '2016-12-14 14:33:29': 1, '2016-12-14 14:33:28': 1, '2016-12-14 13:24:55': 1, '2016-12-14 13:15:51': 1, '2016-12-14 13:05:38': 1, '2016-12-14 12:58:47': 1}
我想按日期时间键对字典进行排序。
我试过了 :
dt = ordereddict.OrderedDict()
但是它不起作用,请帮忙。
将键转换dt
为datetime
对象,例如,使用dateutil.parser.parse
,
from dateutil.parser import parse
from collections import OrderedDict
new_d = OrderedDict(sorted(dt.items(), key=lambda x: parse(x[0])))
print(new_d)
'''
OrderedDict([ ('2016-12-14 12:58:47', 1),
('2016-12-14 13:05:38', 1),
('2016-12-14 13:15:51', 1),
('2016-12-14 13:24:55', 1),
('2016-12-14 14:33:28', 1), ('2016-12-14 14:33:29', 1), ('2016-12-14 14:33:30', 1), ('2016-12-14 14:33:31', 1), ('2016-12-15 05:56:58', 1), ('2016-12-15 07:29:15', 1), ('2016-12-15 08:43:45', 1), ('2016-12-15 09:05:03', 1), ('2016-12-15 15:27:38', 1), ('2016-12-15 15:48:05', 1), ('2016-12-15 15:49:54', 1), ('2016-12-15 15:49:55', 1), ('2016-12-15 15:51:41', 1), ('2016-12-15 15:53:42', 1), ('2016-12-15 17:40:39', 1), ('2016-12-15 18:12:17', 1)])
'''
在您的特定情况下,如@AndreaCorbellini所指出的那样,对字符串进行排序可以很好地工作,即
new_d = OrderedDict(sorted(dt.items()))
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句