echo和printf不会在bash中打印循环中分配的变量

亚历克斯·D。

我有一个带有while循环的脚本，该脚本读取文件并收集一些值。循环停止后，可以再次操纵某些变量：

POWER=$(expect cisco_stats lab-asr9k-2 | awk '!/Total:/ || ++n <= 1' | egrep -v "show envi|CEST|RSP[0-1]")

 while read -r line
    do 
        if [[ $line == "Total:"* ]]
        then t_use=$(echo "$line" | awk '{print $NF}')
            continue
        fi

        if [[ $line == *"Type:"* ]]
        then acdc=$(echo "$line" | awk '{print $NF}')
            continue
        fi

        if [[ $line == "Total Power Capacity:"* ]]
        then t_cap=$(echo "$line" | awk '{print $NF}')
            continue
        fi

        if [[ $line == "Supply Protected Capacity"* ]]
        then np1_av=$(echo "$line" | awk '{print $NF}')
            npn_av="---"
            break
        fi

        if [[ $line == "N+1 Supply Protected"* ]]

        then np1_av=$(echo "$line" | awk '{print $NF}')
            continue
        fi

        if [[ $line == "N+N Supply Protected"* ]]
        then npn_av=$(echo "$line" | awk '{print $NF}')
            break
        fi

    done <<< "$POWER"


if [[ $np1_av == *"Protected"* ]]
then np1_av="Not_Pr."
fi

if [[ $npn_av == *"Protected"* ]]
then npn_av="Not_Pr."
elif [ -z ${npn_av+x} ]
then npn_av="---"
fi

echo "$t_cap"
echo "$t_use"
echo "$acdc"
echo "$np1_av"
echo "$npn_av"

printf "%-10s %-10s %-10s %-10s %-10s\n" "Type" "Tot.cap." "In use" "N+1 prt." "N+N prt."

printf "%-10s %-10s %-10s %-10s %-10s\n" "$acdc" "$t_cap" "$t_use" "$np1_av" "$npn_av"

如果我分别回显每个变量-我会看到正确的结果。如果我尝试在一行中回显或打印变量，那么我只会看到在循环外部设置的变量：

4200W
1266.7
DC
Not_Pr.
---
Type       Tot.cap.   In use     N+1 prt.   N+N prt.  
    Not_Pr.

穆斯塔法·道格鲁（Mustafa DOGRU）

要删除文件的DOS行尾，可以使用它；

POWER=$(expect cisco_stats lab-asr9k-2 | awk '!/Total:/ || ++n <= 1' | egrep -v "show envi|CEST|RSP[0-1]" | sed 's/\r//' )

sed 's/\r//' 是删除文件中的回车

例如;

#!/bin/bash

# add carriage return variables
t_cap=$(echo '4200W' | sed 's/$/\r/')
t_use=$(echo 'DC' | sed 's/$/\r/')
acdc=$(echo 'Not_Pr.' | sed 's/$/\r/')
npn_av=$(echo '---' | sed 's/$/\r/')
np1_av=$(echo 'np1_av' | sed 's/$/\r/')

printf "%-10s %-10s %-10s %-10s %-10s\n" "Type" "Tot.cap." "In use" "N+1 prt." "N+N prt."
printf "%-10s %-10s %-10s %-10s %-10s\n" "$acdc" "$t_cap" "$t_use" "$np1_av" "$npn_av" 


# remove carriage returns
t_cap=$(echo $t_cap | sed 's/\r//')
t_use=$(echo $t_use | sed 's/\r//')
acdc=$(echo $acdc | sed 's/\r//')
np1_av=$(echo $np1_av | sed 's/\r//')
npn_av=$(echo $npn_av | sed 's/\r//')

printf "%-10s %-10s %-10s %-10s %-10s\n" "Type" "Tot.cap." "In use" "N+1 prt." "N+N prt."
printf "%-10s %-10s %-10s %-10s %-10s\n" "$acdc" "$t_cap" "$t_use" "$np1_av" "$npn_av"

当运行这个第二个printf的工作原理如下：

user@host:/tmp/test$ ./test.sh
Type       Tot.cap.   In use     N+1 prt.   N+N prt.  
      - np1_av
Type       Tot.cap.   In use     N+1 prt.   N+N prt.  
Not_Pr.    4200W      DC         np1_av     ---

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