I have an input like below. I want to find out everything starting with abc and ending with mno including lines in between but if abc appears again before mno comes, then I want to ignore the first matched abc. The idea is, I just need a group which starts with abc and ends with mno which are nearest to each other.
test.txt file contains below data:
abc bbb abc yyy mno abc xxx mno
Expected output :
abc yyy mno abc xxx mno
I am using the below grep liner:
grep -ozP "(?s)(abc).\*?(mno)" test.txt
The result is:
abc bbb abc yyy mno abc xxx mno
The first two lines should not be there in the output. Please advise what I can modify in grep to get the desired result.
grep -ozP "(?s)(abc)[^(abc)]*(mno)" 1
abc
yyy
mno
abc
xxx
mno
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