I'm using python 3.3. I have a text file with three lines of text, as an example. I want to select a number and it will display the contents of that line number. For some reason, it prints the line I want, and prints an empty line below it.
The text file looks like this:
AAPL,Apple,700
P,Pandora,32
MW,Men's Warehouse,54.32
The output in the interpreter I get if i is 2:
>>
P,Pandora,32
>>
And the code is here:
line_number = int(input('Enter the line number: '))
with open('C:/Python33/myprogramtests/filewrite1.txt') as f:
i = 1
for line in f:
if i == line_number:
break
i += 1
print (line)
I did try a comma after print (line) but it didn't work. I'm guessing I'm missing some bit of code that would print just the line and not an extra whitespace line.
You should provide an end='' to print to suppress the automatic behaviour of adding the equivalent of \n to output.
I'd also remove the counting logic and use islice to extract the line you wish, eg:
from itertools import islice
line_number = int(input('Enter the line number: '))
with open('yourfile') as fin:
print(next(islice(fin, line_number - 1, line_number), ''), end='')
If you wanted to use the count approach, then you can use enumerate starting at 1, eg:
for idx, line in enumerate(fin, start=1):
if idx == line_number:
print(line, end='')
break
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