I want to convert a number to hex and store the result in a []byte up to length 4. Here's what I came up with, but it feels very roundabout.
package main
import (
"encoding/hex"
"fmt"
)
func main() {
hexstring := fmt.Sprintf("%x", 12345678)
fmt.Println(hexstring)
hexbytes, _ := hex.DecodeString(hexstring)
for {
if len(hexbytes) >= 4 {
break
}
hexbytes = append(hexbytes, 0)
}
fmt.Println(hexbytes)
}
I think there must be a better way to do this using make([]byte, 4) and the encoding/binary package, but I couldn't get it to work.
Sandbox link: http://play.golang.org/p/IDXCatYQXY
Unless I've misunderstood your question, it isn't really about hex at all. You want to take a 32-bit integer, treat it as 4 bytes, and put those bytes into a []byte.
For this, you want the ByteOrder type (actually, its subtypes LittleEndian and BigEndian) from the encoding/binary package. Something like this:
package main
import (
"fmt"
"encoding/binary"
)
func main() {
x := 12345678
b := [4]byte{}
binary.LittleEndian.PutUint32(b[:], uint32(x))
fmt.Println(b)
}
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