I tried the following code to generate random numbers and store them in a HashSet in c#:
class program
{
static void Main(String[] args)
{
Random r=new Random();
HashSet <int> h = new HashSet<int>();
for (int j=0;j<9;++j)
{
h.Add(r.Next(9));
}
int [] array = h.ToArray();
foreach(int i in array)
Console.WriteLine(i);
Console.ReadLine();
}
}
Each time I execute the program, the number of elements being displayed differs. Since I'm using a loop to store 9 values, I expect 9 values to be displayed, which is not happening. What could be the possible error?
HashSet doesn't contain duplicates.Your loop runs 9 times but only unique numbers are added to the HashSet.Add your numbers directly to your array and you should see 9 numbers displaying. Or use a wider range to generate random numbers.Btw you can verify that how many numbers in the HashSet like this, after the for loop:
Console.WriteLine(h.Count);
Alternatively you can change your for loop like this:
for (int j = 0; j < 9; ++j)
{
if(!h.Add(r.Next(9))) j--;
}
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