I am having Input Date as "2020-10-31T00:00:00Z". i want to parse this Date to get Long milliseconds. Note: Converted milliseconds should be in Sydney Time (ie GMT+11).
FYI,
public static long RegoExpiryDateFormatter(String regoExpiryDate)
{
long epoch = 0;
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
df.setTimeZone(TimeZone.getTimeZone("GMT+11"));
Date date;
try {
date = df.parse(regoExpiryDate);
epoch = date.getTime();
} catch (ParseException e) {
System.out.println("Exception is:" + e.getMessage());
e.printStackTrace();
}
System.out.println("Converted regoExpiryDate Timestamp*************** " + epoch);
return epoch;
}
Output: 1604062800000 which gives Date as 30/10/2019 by using Epoch Converter, but in input i'm passing 31st as Date. Can anyone please clarify this?
By doing df.setTimeZone(TimeZone.getTimeZone("GMT+11"));, you are asking the date formatter to interpret your string in the GMT+11 time zone. However, your string shouldn't be interpreted in that timezone. See that Z in the string? That stands for the GMT time zone, so you should have done this instead:
df.setTimeZone(TimeZone.getTimeZone("GMT"));
In fact, your string is in the ISO 8601 format for an Instant (or a "point in time", if you prefer). Therefore, you could just parse it with Instant.parse, and get the number of milliseconds with toEpochMilli:
System.out.println(Instant.parse("2020-10-31T00:00:00Z").toEpochMilli());
// prints 1604102400000
Warning: you shouldn't really use SimpleDateFormat anymore if the Java 8 APIs (i.e. Instant and such) are available. Even if they are not, you should use NodaTime or something like that.
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