I know it has been countlessly asked and I assure you that I've read a lot of posts, articles, etc., and watched a lot of videos but nothing seems to click.
so there we go :
Here are 2 arrays with partial information about every person
let arr1 = [{id:00, name:Ben, city:Philadelphia}, {id:01, name:Alice, city:Frankfurt}, {id:02, name:Detlef, city:Vienna}]
let arr2 = [{id:02, age:18}, {id:00, age:39}, {id:01, age:75}]
And there is the desired final result: an array including the name, city, and age of each person
let arr3 = [{name:Ben, city:Philadelphia, age:39}, {name:Alice, city:Frankfurt, age:75 }, {name:Detlef, city:Vienna, age:18}]
What's the situation? Two arrays both containing objects. each nested object has an id. That id is the common key in each array of objects.
What do you want to do? : I want to create a third array including information from both arrays (from arr1: name and city; from arr2:age).
What have you tried so far? : I couldn't manage to achieve anything worth showing. this minimal example is intended to show you a simple example of my current situation which is: I've got an array that is in the LocalStorage on one hand and an API on the other, both contain some info regarding particular objects (let's say, persons). I want to create an array that will contain all the information regarding each person for easier manipulation afterward (DOM generation, etc.).
I've managed to store both arrays in two "local" arrays but the problem is still there: I can't figure out how to make an array where items are getting their key/value from two separate sources.
Thank you for your help!
You can use reduce method on the arr with array as an inital value, and inside try to find the corrospending item with same id and destruct the object from the id and merge the two object with spread operator.
let arr1 = [{id:00, name:'Ben', city: 'Philadelphia' }, {id:01, name:'Alice', city:'Frankfurt'}, {id:02, name:'Detlef', city:'Vienna'}]
let arr2 = [{id:02, age:18}, {id:00, age:39}, {id:01, age:75}]
const result = arr1.reduce((acc, { id: id1, ...rest1 }) => {
const { id: id2, ...rest2 } = arr2.find(i => i.id === id1)
acc.push({ ...rest1, ...rest2 })
return acc;
}, [])
console.log(result)Collected from the Internet
Please contact [email protected] to delete if infringement.
Comments