Creating a zod enum from an object

Dormati Tech

I have this object:

const properties = [
  { value: "entire_place", label: "The entire place" },
  { value: "private_room", label: "A private room" },
  { value: "shared_room", label: "A shared room" },
] as const;

I need to use it with zod in order to

Validate and parse my data on the backend
Create a typescript union type with those possible values "entire_place" | "shared_room" | "private_room"

According to the zod documentation, i can do this:

const properties = [
  { value: "entire_place", label: "The entire place" },
  { value: "private_room", label: "A private room" },
  { value: "shared_room", label: "A shared room" },
] as const;

const VALUES = ["entire_place", "private_room", "shared_room"] as const;
const Property = z.enum(VALUES);
type Property = z.infer<typeof Property>;

However, I don't want to define my data twice, one time with a label (the label is used for ui purposes), and another without a label.

I want to define it only once using the properties object, without the VALUES array, and use it to create a zod object and infer the type from the zod object.

Any solutions how?

Souperman

In this case, I think I would infer the type for Property from properties directly. You can avoid repeating yourself with code like:

import { z } from "zod";

const properties = [
  { value: "entire_place", label: "The entire place" },
  { value: "private_room", label: "A private room" },
  { value: "shared_room", label: "A shared room" }
] as const;

type Property = typeof properties[number]["value"];
// z.enum expects a non-empty array so to work around that
// we pull the first value out explicitly
const VALUES: [Property, ...Property[]] = [
  properties[0].value,
  // And then merge in the remaining values from `properties`
  ...properties.slice(1).map((p) => p.value)
];
const Property = z.enum(VALUES);

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