Using an algebraic identity about logarithms, logᵢ(N) = log N/log i, so we can take log N out as a factor and the summation is then of 1/log i. Approximating this summation as the integral of 1/log x, we get that asymptotically it is O(N/log N), per Wikipedia. Since we previously took out a factor of log N, multiplying by this gives a final result of O(N).
Collected from the Internet
Please contact [email protected] to delete if infringement.
Comments