printf("\e[2J\e[0;0H");
What does this line mean?
Can I know what to learn and from where to understand this statement?
"\e" as an escape sequence is not part of the C standard.
A number of compilers treat the otherwise undefined behavior as a character with the value of 27 - the ASCII escape character.
Alternative well defined code:
//printf("\e[2J\e[0;0H");
printf("\x1B[2J\x1b[0;0H");
printf("\033[2J\033[0;0H");
#define ESC "\033"
printf(ESC "[2J" ESC "[0;0H");
The escape character introduces ANSI escape sequences as well answered in @Mickael B.. Select terminals implement some of these sequences.
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