I need to get the next element of an array. For contiguous arrays, my code works just fine:
arr=(item{2..5})
value=item3
for ((i=0;i<${#arr[@]};++i)); do
if [[ ${arr[i]} = "$value" ]] && (( i+1<${#arr[@]} )); then
echo "${arr[i+1]}"
break
fi
done
I didn't find any definition of how parameter expansion behaves on sparse arrays and this code unfortunately doesn't yield the desired result either:
arr=([3]=item2 [7]=item3 [10]=item4 [1]=item5)
for ((i=0;i<${#arr[@]};++i)); do
if [[ ${arr[@]:i:1} = "$value" ]]; then
...
...
fi
done
How can I do this for sparse arrays (possibly without the need to copy the array as to reindex it) ?
#!/bin/bash
arr=([3]=item2 [7]=item3 [10]=item4 [1]=item5)
value="item3"
switch="0"
# loop over array's indexes
for i in "${!arr[@]}"; do
if [[ $switch = "1" ]]; then
echo "found ${arr[$i]} in element $i"
switch="0"
break
fi
if [[ ${arr[$i]} = "$value" ]]; then
echo "found ${arr[$i]} in element $i"
switch="1"
continue
fi
done
Output:
found item3 in element 7 found item4 in element 10
The script does not check whether the end of the array has already been reached.
See: help continue
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