Java Program that finds the smallest word from an String array created from user input

The problem comes after reading the input from your scan.nextInt() method of Scanner class, the cursor remains on the same line. so your enter is taken as input when you use nextLine() for first word in the array and that is why it gives 0 as output. . [https://stackoverflow.com/questions/13102045/scanner-is-skipping-nextline-after-using-next-or-nextfoo]

To resolve this, what you can do is that after taking your integer input, consume the left over line by using the nextLine(), then your code works fine as expected, Here is the rectified code :

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {

        // Take user input to start program
        Scanner sc = new Scanner(System.in);
        System.out.println("Please enter the amount of words you'll input:");
        int inputInt = sc.nextInt(); // The size of the array
        sc.nextLine();
        // Set and initialize array
        String[] wordsArray = new String[inputInt];

        // Ask for input and append them to array
        System.out.println("Please input the words of your choice:");
        for (int i = 0; i < inputInt; i++) {
            wordsArray[i] = sc.nextLine();
        } // End of for loop

        // Call method
        System.out.println(minWordLength(wordsArray));

        sc.close();

    }

    public static int minWordLength(String arr[]) {

        String smallestWord = arr[0];
        for (int i = 1; i < arr.length; i++) {
            if (arr[i].length() < smallestWord.length()) {
                smallestWord = arr[i];
            } // End of conditional
        } // End of for loop

        return smallestWord.length();

    }// End of minWordLength2

}

which gives the output :

Please enter the amount of words you'll input:
2
Please input the words of your choice:
abde
as
2