How is temp data stored on the stack frame

Int test(){
    char buff[10]

    printf("Enter text: ");

    gets(buff);

    puts(buff);
}

I don't know how to phrase this question but I'm trying to understand how values are stored on on the buffer allocated for local variables on the stack frame.

---------------
Return Address
---------------
old ebp
---------------
local variables
--------------- 

Is each block 4 bytes and divided in to 4 1 bytes?

------------------
 00 | 40 | 06 | 06
------------------
 ff | ff | de | 70 
------------------

Through gdb I saw the buffer allocated for test was 0x10

I entered sssssssss:

x/x $rbp = 0xffffde70
x/x $rbp + 8 = 0x00400606
x/s $rbp - 16 = "sssssssss"
x/s $rbp - 8 = "\ns"
x/s $rbp - 4 = ""

So how are the characters(in hex) that I entered stored? like how many on each block. It's a 64 system.

 -----------------
 00 | 40 | 06 | 06
------------------
 ff | ff | de | 70 
------------------
    |    |    | 
------------------
    |    |    | s
------------------
 s  | s  | s  | s
------------------
 s  | s  | s  | s 
------------------