def pal(n):
if n[0]==n[len(n)-1] and len(n)!=1:
pal(n[1:len(n)-1])
elif(len(n)==1):
return True
else:
print("Not a Palindrome")
if pal("madam"):
print("Yes, It is a Palindrome")
I have tried to return value as "True" to print if statement. what is the issue with the program?
You could do something like this, you need to return your recursive function. There is also a little mistake, you check for len == 1, this won't always work when it has an even number of characters.
def pal(n):
if len(n) <= 1:
return True
if n[0] == n[-1]:
return pal(n[1:-1])
return False
if pal("madam"):
print("Yes, It is a Palindrome")
else:
print("No, It is not a Palindrome")
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