I would like to compute which part of one duration contains in another duration. There is standard implementation for integers (6), but it gives me 0 (due to integer divison) for the following example:
auto s = 1s;
auto ms = 200ms;
std::cout << ms / s; // 0, but I want 0.2 here
Is there a more elegant and generic way to compute a such value instead of the following ugly solution?
#include <chrono>
#include <iostream>
int main()
{
using namespace std::chrono_literals;
auto s = 1s;
auto ms = 200ms;
const auto part = 1. * ms.count() / std::chrono::duration_cast<decltype(ms)>(s).count();
std::cout << part << '\n';
}
One smart way is to use 1. / (s / ms);, but it's not fit for any duration types.
Use a double based duration.
#include <chrono>
#include <iostream>
int main()
{
using namespace std::chrono_literals;
using my_seconds = std::chrono::duration<double>;
my_seconds s = 1s;
my_seconds ms = 200ms;
std::cout << ms / s << '\n';
}
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