I was trying to get the size of a multidimensional array and wrote code in C as shown below.
#include <stdio.h>
char b[3][4];
int main(void){
printf("Size of array b[3]=%d\n", sizeof(b[3]));
printf("Size of array b[2]=%d\n", sizeof(b[2]));
printf("Size of array b[5]=%d\n", sizeof(b[5]));
return 0;
}
In all above three print statements, I am getting size equal to 4. Can someone explain how sizeof
works in case of a multi-dimensional array? Why is the output the same in the third print?
b
is a 2D character array of rows 3
and columns 4
.
So, if you take sizeof(b)
you will get 12
.
b[0]
(and b[i]
in general) has a type of a 1D character array of size 4
. So. if you take sizeof (b[0])
you will get 4
.
b[0][0]
(and b[i][j]
in general) has a type of char
. So if you take sizeof (b[0][0])
you will get 1
.
sizeof
does not depend on the array index. The type remains the same even for b[0]
and b[100]
, even though it might be out of range of the memory of the array.
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