I would like to know if there was a better way to create a list of list in which each list is a random permutation of an other list. This is what I coded to do it assuming numpy.random is import as rd :
def shuffle(L):
i = rd.randint(0,len(L))
j = rd.randint(0,len(L))
L[i], L[j] = L[j], L[i]
return
list_base= [0,1,2,3]
list_of_list=[]
for k in range(4):
M = list_base
for i in range(5):
shuffle(M)
list_of_list.append(M[:])
Use random.shuffle?
import random
input_list = [0,1,2,3]
shuffled_lists = []
for x in range(4):
lst = input_list[:] # copy, since ...
random.shuffle(lst) # ... this modifies it in-place
shuffled_lists.append(lst)
print(shuffled_lists)
outputs e.g.
[[1, 2, 3, 0], [2, 0, 3, 1], [0, 3, 1, 2], [3, 2, 0, 1]]
This will not guarantee that all permutations in shuffled_lists are unique though!
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