I'm trying to shorten out the following code:
var a = 0, b = 0;
function() {
return a === 0 && b === 0; // returns 'true'
}
So, I thought something like the following would do:
var a = 0, b = 0;
function() {
return a === b === 0; // returns 'false'
}
Initially, I thought that such syntax would throw an error, but apparently it returns false. Why does a === b === 0 return false?
The expression a === b === 0 is interpreted as if it were written (a === b) === 0. The result is false because (a === b) gives true, and true is not === to 0.
One can imagine a programming language that would understand a chain of expressions connected by == or === or whatever, meaning that all values should be compared in one big "group equality" comparison. JavaScript is not such a language, however.
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