I've been debugging this code for about an hour, and it looks like Math.min([1,2]) returns NaN.
var int_array = [1,2]
console.log(Math.min(int_array)) //prints NaN, but expect 1
isNaN(Math.min(int_array))===true
The Math.min() function actually expects a series of numbers, but it doesn't know how to handle an actual array, so it is blowing up.
You can resolve this by using the spread operator ...:
var int_array = [1,2];
console.log(Math.min(...int_array)); // returns 1
You could also accomplish this via the Function.apply() function that would essentially do the same thing but isn't as pretty :
var int_array = [1,2];
console.log(Math.min.apply(null,int_array)); // returns 1
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