Recursive function that returns the remainder

user10158754

I am instructed to define a recursive function in Python that finds the remainder of n divided by b with the condition to not use the "/" ,"%" or "//" operator. I have defined the following function, which works fine for positive numbers. Is there a better way to do this using recursion and simple conditions.

def division(n, b, q = 1):
    """
    parameters : a et b (integers)
    returns: the remainder of a and b
    pre-requisites : q = 1
    """
    if n <= 0 or n < b:
        if n == 0:
            print("Your division has no remainder.")
        elif n in range(0,5):
            print("Your remainder is", n)
        return 0
    else:
        return division(n - b, b, q) + q

print(division(274,5))
Paritosh Singh

I believe your teacher was probably only trying to go for remainders without quotients.

def division(n, b):
    if n < b:
        return n
    return division(n - b, b)
print(division(274, 5))

However, since you brought it up, you can do it with the quotient, without having to start with a 1 for the default.

def division(n, b, q = 0):
    if n < b:
        return n, q
    return division(n - b, b, q + 1)
print(division(274, 5))

Main takeaways, you do not need to check n for range (0,5).

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