I am trying to convert a long to a 4 char array.
It seems like the last char is not being written to the buffer.
Why is this not working?
//convert long to char array
long longValZ = 219902744986400000L;
ByteBuffer bbX = ByteBuffer.allocate(8);
bbX.putLong(longValZ);
//longValZ = 219902744986400000
char [] charArr1 = new char[4];
charArr1[0] = bbX.getChar(0);
charArr1[1] = bbX.getChar(1);
charArr1[2] = bbX.getChar(2);
charArr1[3] = bbX.getChar(3);
long longValX = bbX.getLong(0);
//longValX = 219902744986400000
//convert char array to long
ByteBuffer bbY = ByteBuffer.allocate(8);
bbY.putChar(0,charArr1[0]);
bbY.putChar(1,charArr1[1]);
bbY.putChar(2,charArr1[2]);
bbY.putChar(3,charArr1[3]);
long longValY = bbY.getLong(0);
//longValY = 219902744985600000 --> why is longValY different than longValZ ?
You don't need to provide the index
long longValZ = 219902744986400000L;
ByteBuffer bbX = ByteBuffer.allocate(8);
bbX.putLong(longValZ);
char[] charArr1 = new char[4];
for (int i = 0; i < charArr1.length; i++)
charArr1[i] = bbX.getChar();
//convert char array to long
ByteBuffer bbY = ByteBuffer.allocate(8);
for (int i = 0; i < charArr1.length; i++)
bbY.putChar(charArr1[i]);
long longValY = bbY.getLong(0);
Collected from the Internet
Please contact [email protected] to delete if infringement.
Comments