Ok, I am 500th user asking this question, I read many answers but still having no luck.
parent module pom contains:
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-web</artifactId>
<version>${spring.framework.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>${spring.framework.version}</version>
</dependency>
Child module has maven-jetty-plugin and I run my webapp module with jetty:run.
web.xml defines standard dispatcher module:
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
I have file dispatcher-servlet.xml under WEB-INF, though start fails with:
FileNotFoundException: Could not open ServletContext resource [/WEB-INF/applicationContext.xml]
What is wrong? Documentation and everybody says that Spring MVC will search for XX-servlet.xml, where XX is name of servlet. Why does it search for applicationContext.xml?
ContextLoaderListener has its own context which is shared by all servlets and filters. By default it will search /WEB-INF/applicationContext.xml
You can customize this by using
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/somewhere-else/root-context.xml</param-value>
</context-param>
on web.xml, or remove this listener if you don't need one.
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