I'm attempting to learn how to use lua/luabridge to call member function of a class, but I'm having some trouble:
Here is the simple test class:
class proxy
{
public:
void doSomething(char* str)
{
std::cout << "doDomething called!: " << str << std::endl;
}
};
And the code that uses it:
int main()
{
lua_State* L = luaL_newstate();
luaL_openlibs(L);
proxy p;
luabridge::getGlobalNamespace(L)
.beginClass<proxy>("proxy")
.addFunction("doSomething", &proxy::doSomething)
.endClass();
std::string filename("test.lua");
if (luaL_dofile(L, filename.c_str()) || lua_pcall(L, 0, 0, 0)) {
std::cout << "Error: script not loaded (" << filename << ")" << std::endl;
L = 0;
return -1;
}
return 0;
}
And finally, the lua script:
proxy:doSomething("calling a function!")
There is probably several errors here, but specifically what I want to do, is call the the member function for the proxy instance, from the lua script, as if I was calling:
p.doSomething("calling a function!");
I'm aware that there are a lot of similar questions, but none I have found so far directly answers my question.
Currently the script does not even load/execute so I'm a bit puzzled.
As it turned out, I had to change the code to:
int main()
{
lua_State* L = luaL_newstate();
luaL_openlibs(L);
proxy p;
luabridge::getGlobalNamespace(L)
.beginClass<proxy>("proxy")
.addFunction("doSomething", &proxy::doSomething)
.endClass();
std::string filename("test.lua");
if (luaL_dofile(L, filename.c_str())) {
std::cout << "Error: script not loaded (" << filename << ")" << std::endl;
L = 0;
return -1;
}
// new code
auto doSomething = luabridge::getGlobal(L, "something");
doSomething(p);
return 0;
}
And change the script:
function something(e)
e:doSomething("something")
end
This actually works better for me. The script wouldn't work because the lua stack didn't know anything about the proxy instance, and I had to call a lua function directly, which, in turn, called the class member function.
I don't know if there is an easier way to do it, but this is good enough for me.
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