Issue
How can I remove last line for this sed cycle?
sed -n '/## bash, file, re/,/##/p' bash.kb
In my case, it shows me the last line too, last line with ## string, which I need to remove.
Example.
Source file bash.kb, this is text file.
...
## bash, file, remove last character on every line
sed 's/.$//' $file
## bash, files, watch only today's modified files
some command.
some 2nd command.
## bash, file, remove duplicate rows by column 1
sort -u -t, -k1,1 $file
## bash, file, exclude
command exclude
command exclude 2
## bash, file, remove all whitespaces from file
command
...
When I enter this command.
sed -n '/## bash, file, re/,/##/p' bash.kb
It will search for ## bash, file, re and display output until next ##, so with next ## head line, which I need to remove.
## bash, file, remove last character on every line
sed 's/.$//' $file
## bash, files, watch only today's modified files
## bash, file, remove duplicate rows by column 1
sort -u -t, -k1,1 $file
## bash, file, exclude
## bash, file, remove all whitespaces from file
command
Output should be like this (implement sed '$d' to every cycle? But how?).
## bash, file, remove last character on every line
sed 's/.$//' $file
## bash, file, remove duplicate rows by column 1
sort -u -t, -k1,1 $file
## bash, file, remove all whitespaces from file
command
Thanks.
If your input file has an empty line before every ## line and only there, you can specify an empty line as the end of your range:
sed -n '/## bash, file, re/,/^$/p' bash.kb
^$ matches a line that has the beginning (^), the end of the line ($) and nothing in between.
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