I have a javascript function as below :
function modifyx(xvalue) {
val = 1;
for (x = 0; x < 10; x++) {
val = val + 1;
}
return val;
}And the main snippet passes a variable named x to the above function as below:
for (x = 0; x < 10; x++) {
console.log(modifyx(x));
}The expected output should be "11" printed 10 times but instead it prints one time. The function call changes the value of x eventhough i am not modifying the passed value. The x inside the function has it's own scope. Yet it gets modified. Any help on this would be highly appreciated.
The variable x in your code is global. When your method modifyx(xvalue) returns for the first time the value of x is already 11 which is used in the for loop for the second iteration. Thus it fails to execute the method further.
Use let x in the declaration in for (x = 0; x < 10; x++) to create a unique execution environment.
function modifyx(xvalue) {
val = 1;
for (x = 0; x < 10; x++) {
val = val + 1;
}
return val;
}
for (let x = 0; x < 10; x++) {
console.log(modifyx(x));
}Collected from the Internet
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