Important: If the value is a list, then I want to get multiple key, value tuples for that key and each item in the list. The values in the dictionary will be of multiple types, including at least strings, ints, and lists.
I have a solution, below, but I'm wondering if there's a more concise way to do this.
# Sample data
d = {'key1': 'string1',
'key2': 15,
'key3': ['item1', 'item2', 'item3', 'item4']}
# This code does what I want
parameters = []
for k, v in d.iteritems():
if isinstance(v, str):
parameters.append((k ,v))
elif isinstance(v, int):
parameters.append((k, v))
elif isinstance(v, list):
for x,y in zip(itertools.repeat(k), v):
parameters.append((x, y))
else:
continue
parameters
# [('key1', 'string1'),
# ('key2', 15),
# ('key3', 'item1'),
# ('key3', 'item2'),
# ('key3', 'item3'),
# ('key3', 'item4')]
Here is a shorter version with list comprehension:
>>> d = {'key1': 'string1', 'key2': 15, 'key3': ['item1', 'item2', 'item3', 'item4']}
>>> parameters = [(k, v1) for k, v in d.iteritems() for v1 in (v if isinstance(v, list) else [v])]
>>> parameters
[('key3', 'item1'), ('key3', 'item2'), ('key3', 'item3'), ('key3', 'item4'), ('key2', 15), ('key1', 'string1')]
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