数据类型在函数调用中不匹配

卡方

我在为自己编写的功能匹配数据类型时遇到麻烦，

该函数是：

void generate_all_paths(int size, char *maze[][size], int x, int y) {
   ...
}

参数size，x和y都非常简单。我相信是迷宫把我赶走了。它旨在成为多维尺寸x尺寸数组，包含像迷宫一样的字母字符。

当我尝试像这样在main中调用函数时：

int main() {
    char *exmaze[][6] = { {"#","#","#","#","#","#"},
        {"S","a","#","h","l","n"},
        {"#","b","d","p","#","#"},
        {"#","#","e","#","k","o"},
        {"#","g","f","i","j","#"},
        {"#","#","#","#","#","#"}
    };
    generate_all_paths(6, *exmaze, 1, 0);
    return 0;
}

我的IDE抱怨没有用参数的数据类型匹配的generate_all_paths函数。

我可以肯定的是，我的问题主要出在我定义了exmaze的地方，但是我的调整无法解决它。

有人有什么建议吗？谢谢！

托马斯·斯伯伯

我认为，使用模板是最优雅的方法：

template<int size>
void generate_all_paths(const char *maze[][size], int x, int y) {
    ...
}

int main() {
    const char *exmaze[][6] = { {"#","#","#","#","#","#"},
        {"S","a","#","h","l","n"},
        {"#","b","d","p","#","#"},
        {"#","#","e","#","k","o"},
        {"#","g","f","i","j","#"},
        {"#","#","#","#","#","#"}
    };
    generate_all_paths(exmaze, 1, 0);
    return 0;
}

还请注意const char [] []！

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