我创建了一个测验页面,用于将登录用户的测验结果存储到排行榜中。
我有一个表,名为users,具有user和quiz_score列。根据登录用户进行测验的结果,我可以打印出排行榜。我在他们的个人资料页面上的排行榜中显示特定用户的位置时遇到问题。如果它们在前三名中,我还想附加一枚奖章(例如jpeg图像)。这是到目前为止我用于排行榜的代码:
<?php
require_once 'header.php';
// Send variables for the MySQL database class.
$database = mysql_connect('localhost', 'root', 'password') or die('Could not connect: ' . mysql_error());
mysql_select_db('robinsnest') or die('Could not select database');
$query = "SELECT * FROM `members` ORDER by `quiz_score` DESC LIMIT 10";
$result = mysql_query($query) or die('Query failed: ' . mysql_error());
$num_results = mysql_num_rows($result);
echo '<div class="container marketing">
<div class="col-xs-12 col-sm-8 col-md-6 col-sm-offset-2 col-md-offset-3">
<table class="gradienttable">
<tr>
<th>Position</th>
<th>User Name</th>
<th>Score</th>
</tr>';
for($i = 1; $i <= $num_results; $i++)
{
$row = mysql_fetch_array($result);
echo "<tr>
<td>".$i."</td>
<td>".$row['user']."</td>
<td>".$row['quiz_score']."</td>
</tr>";
}
echo "</table>
</div>
</div>";
echo"<hr class='featurette-divider'>";
echo ' <footer>
<p class="pull-right"><a href="#">Back to top</a></p>
<p>2015 Students-NCI, · <a href="#">Privacy</a> · <a href="#">Terms</a></p>
</footer>';
?>
</body>
</html>
到目前为止,我拥有用于打印出用户分数的代码:
<?php
require_once 'header.php';
$database = mysql_connect('localhost', 'root', 'password') or die('Could not connect: ' . mysql_error());
mysql_select_db('robinsnest') or die('Could not select database');
$query = "SELECT user, quiz_score, FIND_IN_SET( quiz_score, (
SELECT GROUP_CONCAT( quiz_score
ORDER BY quiz_score DESC )
FROM members )
) AS rank
FROM members
WHERE user = '$user';";
$result = mysql_query($query) or die('Query failed: ' . mysql_error());
$num_results = mysql_num_rows($result);
echo "<p>".$query."</p>";
echo"<hr class='featurette-divider'>";
echo ' <footer>
<p class="pull-right"><a href="#">Back to top</a></p>
<p>2015 Students-NCI, · <a href="#">Privacy</a> · <a href="#">Terms</a></p>
</footer>';
?>
</body>
</html>
仅打印sql查询的字符串,不会打印出登录用户的位置。我尝试了一些不同的方法,但是没有成功。
任何帮助将不胜感激。
for loop()
,而是使用while loop()
来查询。我知道您通过查询结果的数量来循环它,但是它只会得到第一行的值。如果分配循环的当前编号并将其作为数组附加到变量,则可能是可行的。$ranking
,该计数器将在每个循环中递增(删除了$num_results
,因为您不再需要它了)。?>
在继续进行HTML之前,用封闭了PHP 。while loop
。您的固定代码:
<?php
require_once 'header.php';
// Send variables for the MySQL database class.
$database = mysql_connect('localhost', 'root', 'password') or die('Could not connect: ' . mysql_error());
mysql_select_db('robinsnest') or die('Could not select database');
$query = "SELECT * FROM `members` ORDER by `quiz_score` DESC LIMIT 10";
$result = mysql_query($query) or die('Query failed: ' . mysql_error());
$num_results = mysql_num_rows($result);
$ranking = 1;
?>
<div class="container marketing">
<div class="col-xs-12 col-sm-8 col-md-6 col-sm-offset-2 col-md-offset-3">
<table class="gradienttable">
<tr>
<th>Position</th>
<th>User Name</th>
<th>Score</th>
</tr>
<?php
while($row = mysql_fetch_array($result)){
?>
<tr>
<td><?php echo $ranking; ?></td>
<td><?php echo $row['user']; ?></td>
<td><?php echo $row['quiz_score']; ?></td>
<?php
$ranking = $ranking + 1; /* INCREMENT RANKING BY 1 */
?>
</tr>
<?php
} /* END OF WHILE LOOP */
?>
</table>
</div>
</div>
<hr class="featurette-divider">
<footer>
<p class="pull-right"><a href="#">Back to top</a></p>
<p>2015 Students-NCI, · <a href="#">Privacy</a> · <a href="#">Terms</a></p>
</footer>
</body>
</html>
您的第二个给定代码:
<?php
require_once 'header.php';
$database = mysql_connect('localhost', 'root', 'password') or die('Could not connect: ' . mysql_error());
mysql_select_db('robinsnest') or die('Could not select database');
$query = "SELECT user, quiz_score, FIND_IN_SET( quiz_score, (
SELECT GROUP_CONCAT( quiz_score
ORDER BY quiz_score DESC )
FROM members )
) AS rank
FROM members
WHERE user = '$user';";
$result = mysql_query($query) or die('Query failed: ' . mysql_error());
$num_results = mysql_num_rows($result);
while($row = mysql_fetch_array($result)){
?>
<p><?php echo $row['user']." - ".$row['quiz_score']; ?></p>
<?php
} /* END OF WHILE LOOP */
?>
<hr class="featurette-divider">
<footer>
<p class="pull-right"><a href="#">Back to top</a></p>
<p>2015 Students-NCI, · <a href="#">Privacy</a> · <a href="#">Terms</a></p>
</footer>';
</body>
</html>
prepared statement
而不是不推荐使用的mysql_*
函数来防止SQL注入。本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
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